Title: Snap 2023 Slot 1 Question Paper with Indian Game Solutions
Question 1:
In a game of cards, 3 cards are drawn from a well-shuffled deck of 52 cards. Find the probability that all 3 cards are of the same suit.
Solution:
To find the probability, we first calculate the total number of ways to draw 3 cards from a deck of 52 cards. This is given by the combination formula:
C(n, r) = n! / (r!(n-r)!)
Where n is the total number of items, r is the number of items to choose, and "!" denotes factorial.
For 3 cards from 52 cards:
C(52, 3) = 52! / (3!(52-3)!) = (52 × 51 × 50) / (3 × 2 × 1) = 22,100
Now, we calculate the number of ways to draw 3 cards of the same suit. There are 4 suits in a deck (Hearts, Diamonds, Clubs, and Spades), and each suit has 13 cards.
Number of ways to choose 3 cards of the same suit:
C(13, 3) = 13! / (3!(13-3)!) = (13 × 12 × 11) / (3 × 2 × 1) = 286
Since there are 4 suits, we multiply the number of ways to choose 3 cards of the same suit by 4:
Total number of ways to draw 3 cards of the same suit = 4 × 286 = 1,144
Finally, we calculate the probability:
Probability = (Number of favorable outcomes) / (Total number of outcomes)
Probability = 1,144 / 22,100 ≈ 0.0519 or 5.19%
Question 2:
A game involves rolling a fair six-sided die twice. Find the probability that the sum of the two rolls is 7.
Solution:
To find the probability, we list all the possible outcomes of rolling a die twice and count the ones that result in a sum of 7.
When rolling two six-sided dice, there are 6 possible outcomes for the first die and 6 possible outcomes for the second die, giving us a total of 6 × 6 = 36 possible outcomes.
The pairs of numbers that sum up to 7 are:
(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1)
There are 6 pairs that sum to 7.
Probability = (Number of favorable outcomes) / (Total number of outcomes)
Probability = 6 / 36 = 1 / 6 ≈ 0.1667 or 16.67%
Question 3:
A game consists of 10 players, each of whom is assigned a number from 1 to 10. A draw is made to determine the order of play. Find the probability that player 1 will play before player 9.
Solution:
Since the draw is made randomly and all players have an equal chance of being assigned any position, the probability that player 1 will play before player 9 is the same as the probability that any two specific players will play in that order.
When player 1 plays, there are 9 possible positions where player 9 can be. Out of these 9 positions, 1 of them is the one where player 9 plays after player 1, and the remaining 8 positions are where player 9 plays before player 1.
Probability = (Number of favorable outcomes) / (Total number of outcomes)
Probability = 1 / 9 ≈ 0.1111 or 11.11%
Note: These solutions assume that the games are fair and that each outcome is equally likely.
SNAP 2023 Slot 1 Question Paper: Game-Based Reasoning & Problem-Solving Solutions
SNAP (Symbiosis National Admissions Process) 2023 Slot 1 exam primarily tests analytical, logical, and verbal skills. Below is a structured guide to solving game-based and logic-related questions commonly found in SNAP 2023, along with sample problems and solutions.
1. Game-Based Reasoning
SNAP often includes puzzles involving sequences, permutations, or logical games.
Example Question:
A group of 6 friends—A, B, C, D, E, and F—play a game where they stand in a circle. Each person is assigned a unique number from 1 to 6. The rule is that a person can only move clockwise if their number is higher than the person to their left. Starting with A (number 3), determine the final order after all valid moves are made.
Solution:
Initial Order (clockwise): A(3), B(5), C(1), D(6), E(2), F(4).
Valid Moves:
B(5) > A(3) → moves left to A’s position.
D(6) > C(1) → moves left.
F(4) > E(2) → moves left.
Final Order: D(6), F(4), B(5), A(3), E(2), C(1).
Key Insight: Numbers "jump over" smaller values clockwise until no more moves are possible.
2. Logical Seating Arrangement
Sample Question:
8 people are seated around a circular table. K, L, M, N, O, P, Q, and R are part of a debate team. K sits opposite O. L is to the immediate right of M. N is between P and Q. If R sits next to L, who is seated between K and N?
Solution:
Circles: Assign positions 1–8 clockwise.
Clues:
K opposite O → K(1) ↔ O(5).
L right of M → M(2), L(3).
N between P and Q → P(4), N(5), Q(6).
R next to L → R(4) or R(2).
Conflict Resolution: O is at 5, so N cannot be at 5. Adjust:
P(6), N(7), Q(8).
R must be at 4 (next to L(3)).
Final Arrangement:
1: K, 2: M, 3: L, 4: R, 5: O, 6: P, 7: N, 8: Q.
Answer: O is between K and N.
3. Data Interpretation (Game Scores)
Sample Question:
A tournament has 4 teams (Alpha, Beta, Gamma, Delta) playing 3 matches each. The table shows points scored per game. Who has the highest average score per match?
Team
Match 1
Match 2
Match 3
Alpha
12
15
10
Beta
10
14
16
Gamma
8
18
12
Delta
14
13
15
Solution:
Alpha: (12+15+10)/3 = 12.67
Beta: (10+14+16)/3 = 13.67
Gamma: (8+18+12)/3 = 12.67
Delta: (14+13+15)/3 = 13.67
Answer: Beta and Delta tie for the highest average.
4. Verbal Reasoning: Analogies in Games
Sample Question:
If "Checkers is to跳棋 (checkers) as Chess is to __":
Solution:
Pattern: Both pairs are board games with strategic elements.
Answer: "国际象棋 (chess)" → Gaming.
5. Time Management Tips
Prioritize High-Weightage Sections: Focus on logical reasoning and data interpretation first.
Elimination Techniques: Use process of elimination in multiple-choice questions.
Game-Based Practice: Solve puzzles involving sequences, seating, and averages.
Final Note: SNAP 2023 Slot 1 emphasized speed and accuracy in logic and data analysis. Candidates should practice 30+ game-based puzzles weekly and review past SNAP papers.
For more solved examples or specific topics, let me know! 🎯
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